Belgian general election, August 1870
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All 124 seats in the Chamber of Representatives 63 seats needed for a majority |
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Early general elections were held in Belgium on 2 August 1870, the second that year after the partial elections in June had ended with both the Catholic Party and the Liberal Party holding 61 seats each.[1] The result was a victory for the Catholic Party, which won 72 of the 124 seats in the Chamber of Representatives and 34 of the 62 seats in the Senate.[1] Voter turnout was 68%,[2] although only 107,099 people (2.1% of the population) were eligible to vote.[1]
Results
Chamber of Representatives
| Party | Votes | % | Seats | +/– | |
|---|---|---|---|---|---|
| Catholic Party | 39,705 | 54.5 | 72 | +11 | |
| Liberal Party | 32,448 | 44.5 | 52 | –9 | |
| Others | 720 | 1.0 | 0 | New | |
| Invalid/blank votes | 6,210 | – | – | – | |
| Total | 79,083 | 100 | 124 | +2 | |
| Registered voters/turnout | 107,099 | 68.0 | – | – | |
| Source: Mackie & Rose,[2] Sternberger et al | |||||
Senate
| Party | Votes | % | Seats |
|---|---|---|---|
| Catholic Party | 34 | ||
| Liberal Party | 27 | ||
| Independents | 1 | ||
| Total | 62 | ||
| Sternberger et al. | |||
