United States presidential election in Kentucky, 1948
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All 11 Kentucky votes to the Electoral College |
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The 1948 United States presidential election in Kentucky took place on November 2, 1948, as part of the 1948 United States presidential election. Kentucky voters chose eleven[2] representatives, or electors, to the Electoral College, who voted for President and Vice President.
Kentucky was won by incumbent President Harry S. Truman (D–Missouri), running with Senator Alben W. Barkley, with 56.74% of the popular vote, against Governor Thomas Dewey (R–New York), running with Governor Earl Warren, with 41.48% of the popular vote.[3][4]
Results
| United States presidential election in Kentucky, 1948 | ||||
|---|---|---|---|---|
| Party | Candidate | Votes | % | |
| Democratic | Harry S. Truman (inc.) | 466,756 | 56.74% | |
| Republican | Thomas Dewey | 341,210 | 41.48% | |
| Dixiecrat | Strom Thurmond | 10,411 | 1.27% | |
| Write-in | 4,281 | 0.52% | ||
| Total votes | 822,658 | 100% | ||
References
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| General articles |
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| Local results |
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| Other 1948 elections |
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