United States presidential election in Virginia, 1992
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450px County Results
Clinton—>70%
Clinton—60-70%
Clinton—50-60%
Clinton—40-50%
Bush—40-50%
Bush—50-60%
Bush—60-70%
Bush—>70%
Perot—40-50%
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The 1992 United States presidential election in Virginia took place on November 3, 1992, as part of the 1992 United States presidential election. Voters chose thirteen representatives, or electors to the Electoral College, who voted for President and Vice President.
Virginia was won by incumbent President George H.W. Bush (R-Texas) with 44.97% of the popular vote over Governor Bill Clinton (D-Arkansas) with 40.59%. Businessman Ross Perot (I-Texas) finished in third with 13.63% of the popular vote.[1] Clinton ultimately won the national vote, defeating both incumbent President Bush and Perot.[2]
Results
United States presidential election in Virginia, 1992[1][3] | |||||
---|---|---|---|---|---|
Party | Candidate | Votes | Percentage | Electoral votes | |
Republican | George H.W. Bush (inc.) | 1,150,517 | 44.97% | 13 | |
Democratic | Bill Clinton | 1,038,650 | 40.59% | 0 | |
Independent | Ross Perot | 348,639 | 13.63% | 0 | |
Democrats for Economic Recovery | Lyndon LaRouche | 11,937 | 0.47% | 0 | |
Libertarian | Andre Marrou | 5,730 | 0.22% | 0 | |
New Alliance Party | Lenora Fulani | 3,192 | 0.12% | 0 | |
Totals | 2,558,665 | 100.0% | 13 |
References
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- ↑ http://clerk.house.gov/member_info/electionInfo/1992election.pdf